最近需要频繁的登录4A系统,可是移动效率如此低下,申请个账号好几个月了还不行。
无奈,好多同事共用同一账号,但是每次都需要将手机号改为自己的。好麻烦。 今天加班,事情不多。写个脚本替我做吧。class="java">public class Modify4ATempMobile{
private static HttpClient client = null;
public static void main(String[] args) throws Exception {
String loginURL = "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=getPwdProtectBeforeLoginForTempMobile";
String checkURL = "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=checkPwdProtectBeforeLoginForTempMobile";
String updateURL = "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=setTempMobile";
Map<String, String> param = new HashMap<String, String>();
param.put("userId", "crm_xxx");
param.put("authCode", "xxx12345");
System.out.println(doPost(loginURL, param));
param.clear();
param.put("question", "xx");
param.put("answer", "xx");
System.out.println(doPost(checkURL, param));
param.clear();
param.put("tempmobile", "13814027174");
System.out.println(doPost(updateURL, param));
}
public static String doPost(String url, Map<String, String> parameters) throws IOException {
//使用同一个client,保持session
if(client == null){
client = getHttpClient();
}
PostMethod method = new PostMethod(url);
if(parameters != null && !parameters.isEmpty()){
NameValuePair[] list = new NameValuePair[parameters.size()];
int i = 0;
Entry<String, String> entry = null;
for(Iterator<Entry<String, String>> iterator = parameters.entrySet().iterator(); iterator.hasNext(); ){
entry = (Entry<String, String>) iterator.next();
list[i++] = new NameValuePair(entry.getKey(), entry.getValue());
}
method.setRequestBody(list);
}
client.executeMethod(method);
return method.getResponseBodyAsString();
}
public static HttpClient getHttpClient(){
HttpClient client = new HttpClient();
//代理设置,不用可以去掉
client.getHostConfiguration().setProxy("proxy.bmcc.com.cn", 8080);
client.getParams().setAuthenticationPreemptive(true);
//如果代理需要密码验证,这里设置用户名密码
client.getState().setProxyCredentials(AuthScope.ANY, new UsernamePasswordCredentials("ngcrm_xxx","xxx"));
//end 代理
client.getHttpConnectionManager().getParams().setConnectionTimeout(0);
client.getHttpConnectionManager().getParams().setSoTimeout(0);
return client;
}
}
?
跑了下,没有问题,完美解决问题。@echo off setlocal enabledelayedexpansion set work_path=D:\Work-bj\crm_bj\lib d: cd %work_path% for %%F in (%work_path%\apache\*.jar) do call :addcp %%F for %%F in (%work_path%\appframe\*.jar) do call :addcp %%F for %%F in (%work_path%\other\*.jar) do call :addcp %%F for %%F in (%work_path%\runtime\*.jar) do call :addcp %%F set classpath= .;D:/Work-bj/crm_bj/html/WEB-INF/classes;%CLASSPATH% java com.asiainfo.test.Modify4ATempMobile pause :addcp echo %1 SET CLASSPATH=%CLASSPATH%;%1? 4.改用VBS试试 做完后觉得不错,可是想想太土了。能不能简单点呢。突然就想用vbs试试。虽然没写过,不过不就是代码嘛,试试。 ?
Const userId="crm_xxx"
Const passwd="xxx12345"
Const question="xxx"
Const answer="xxx"
Const tempmobile="13814027174"
Dim http
Set http = CreateObject("Msxml2.XMLHTTP")
http.open "POST", "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=getPwdProtectBeforeLoginForTempMobile", False
http.setRequestHeader "CONTENT-TYPE","application/x-www-form-urlencoded"
http.send "authCode=" & passwd & "&userId=" & userId
http.open "POST", "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=checkPwdProtectBeforeLoginForTempMobile", False
http.setRequestHeader "CONTENT-TYPE","application/x-www-form-urlencoded"
http.send "question=" & question & "&answer=" & answer
http.open "POST", "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=setTempMobile", False
http.setRequestHeader "CONTENT-TYPE","application/x-www-form-urlencoded"
http.send "tempmobile=" & tempmobile
?
5.继续完善下Set ie = CreateObject("InternetExplorer.Application")
ie.visible=true
ie.Navigate "http://4aportal.bmcc.com.cn/"
do until 4=ie.readyState
do until 4=ie.readyState
waittime = waittime + 200
if waittime > 15000 then exit do
Loop
Loop
if 4<>ie.readyState then
ie.quit
WScript.quit
end if
set dom = ie.document
set form = dom.getElementById("logonForm")
form.all("name").value = userId
form.all("pwd").value = passwd
'短信登录
'form.all("button4").click()
'语音登录
form.all("button5").click()
?
自动登陆完成后,我就意识到,能不能将整个过程都做成可视化的,自动的呢。毕竟后台改数据,出问题也不好定位。经过研究,最终结果如下。
'请修改信息为需要的信息。
'用户名
Const userId = "crm_xxx"
'密码
Const passwd = "xxx12345"
'密保问题
Const question = "xxx"
'密保答案
Const answer = "xxx"
'临时手机号
Const tempmobile = "13814027174"
'短信登录:1 语音登录:2
Const logintype = 2
' 如果打开默认的ie呢
Set ie = CreateObject("InternetExplorer.Application")
ie.Visible = true
ie.Top = 0
ie.Left = 0
ie.Navigate "http://4aportal.bmcc.com.cn/iam/belogin/login_findpwdproduct_tempmobile.jsp"
wait4ieready()
'发送alt+空格+x最大化
Set WshShell = WScript.CreateObject("WScript.Shell")
WshShell.SendKeys "%+(' 'x)"
ie.document.getelementByid("userId").value = userId
ie.document.getelementByid("authCode").value = passwd
ie.document.getelementByid("confirm").click()
wait4ieready()
ie.document.getElementById("answer").value = answer
ie.document.getElementById("confirm").click()
wait4ieready()
ie.document.getElementById("tempmobile").value = tempmobile
ie.document.getElementById("confirm").click()
wait4ieready()
ie.document.getElementById("skip").click()
wait4ieready()
ie.document.getElementById("name").value = userId
ie.document.getElementById("pwd").value = passwd
if logintype = 1 then
'短信登录
form.all("button4").click()
else
'语音登录
ie.document.getElementById("button5").click()
end if
sub wait4ieready()
do while ie.ReadyState <> 4 or ie.busy
wscript.sleep 200
loop
end sub
??
总结
这样好多了,不得不说,看起来好玩多了。