字符串处理技巧1_JAVA_编程开发_程序员俱乐部

class="java">		String s = "3a1bd2caea1dcd2dcba45";
		char[] charArray = s.toCharArray(); 
		Map<String, Integer> map = new LinkedHashMap<String, Integer>();
		for (int i = 0; i < charArray.length; i++) {
			if(map.containsKey(String.valueOf(charArray[i]))){
				map.put(String.valueOf(charArray[i]), map.get(String.valueOf(charArray[i])) + 1);
			}else {
				map.put(String.valueOf(charArray[i]), 1);
			}
		}
		System.out.println(map); :wink: 

{3=1, a=4, 1=2, b=2, d=4, 2=2, c=3, e=1, 4=1, 5=1}