java逆转单链表_JAVA_编程开发_程序员俱乐部

class="java" name="code">
//节点类
class Node{
	public Node(int value){
		this.value = value;
	}
	public Node(){
	}
	int value;
	Node next;
}

//初始化一个有序的单链表
	public Node initList(){
		Node head = new Node();
		Node n1 = new Node();
		Node n2 = new Node();
		Node n3 = new Node();
		Node n4 = new Node();
		Node n5 = new Node();
		n1.value = 1;
		n2.value = 2;
		n3.value = 3;
		n4.value = 4;
		n5.value = 5;
		n1.next = n2;
		n2.next = n3;
		n3.next = n4;
		n4.next = n5;
		head.next = n1;
		return head;
	}

//单链表逆转，非递归
	public Node reverseList(Node node){
		if (null == node) {   
            return node;   
        }
		//上一个节点
        Node upper = null;   
        //当前节点
        Node cur = node.next;
        //下一个节点
        Node next = null;   
        while (null != cur) {   
            next = cur.next;   
            cur.next = upper;
            upper = cur;   
            cur = next;   
        }
        //反转结束后,upper引用指向原链表的最后一个节点，即反转后的第一个节点
        node = upper;   
           
        return node;   
	}

public Node reverse(Node node){
		if(node==null || node.next == null)return node;
		Node next = node.next;
//将node的next清空，否则在递归return到最上层时要逆转的原链表的最后一个节点的next会指向原来的头节点，而原来的头节点的next又指向原来的第一个节点，即逆转后的最后一个节点，会造成无限的重复链表
		node.next = null;
		Node returnNode = reverse2(next);
		next.next = node;
		return returnNode;
	}

//打印单链表
	public void printList(Node head){
		String str = "";
		for(Node n = head;n!=null;){
			str = str + " " + n.value;
			n = n.next;
		}
		System.out.println(str);
	}

Test t = new Test();
		Node head = t.initList();
		System.out.println("逆转前:");
		t.printList(head.next);
		System.out.println("逆转后:");
		t.printList(t.reverseList(head));